answer:Step 1: Identify keywords in the review. Keywords: "cute", "fun", "silly", "Really silly", "crazy", "cool cows", "fun to read", "kids really like it". Step 2: Determine the sentiment of the keywords. Most keywords seem to be associated with positive sentiments, such as "cute", "fun", "silly", "crazy", "cool cows", "fun to read", and "kids really like it". The only potentially negative keyword is "Nope", however, it is used to mention the lack of believability, which doesn't necessarily mean it is a negative sentiment. Step 3: Analyze the overall sentiment of the review. After evaluating the sentiment of the keywords and considering the context, it is clear that the review is mainly positive. The user enjoyed the book, found it fun to read, and mentioned that their kids really liked it. Result: The review is positive.

answer:In addition to the Grauman's Chinese Theater, the first TCM Classic Film Festival took place at the Grauman's Egyptian Theater in Hollywood.

answer:This sentence is in German. Here's a translation for better understanding: "The effort in the household in 1997 is very high, and the available information from the member states indicates ambitious expenditure targets for 1998." The context appears to be related to budgetary or financial matters, possibly in a European Union setting, as it mentions member states.

answer:Yes, I understand the problem. To solve it, we need to find the longest common substring (sequence of characters) in the two given strings A and B. Given strings A = "BWdpoKAUzlYfA" and B = "ipVTCPoKAUzliYnl" The definition of common substring is that the characters appear in the same order in both strings. So, we can just iterate through the characters in both strings and keep track of the longest common substring we've found so far. 1. Create a table to store the length of common substrings found. Initialize all elements in the table to 0. The table will have rows equal to the length of string A + 1, and columns equal to the length of string B + 1. 2. Iterate through both strings with nested loops. In each iteration, compare the characters at the current positions in the strings. a. If the characters are equal, update the table cell(i+1, j+1) = table cell(i, j) + 1. b. If the characters are not equal, table cell(i+1, j+1) will remain 0. 3. Keep track of the maximum length and ending position found. 4. Once the iteration is done, reconstruct the longest common substring by iterating back from the end position. Here's the detailed process for the given strings: Table initialized to all 0's: 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 i p V T C P o K A U z l i Y n l 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 B 1 0 W 2 0 d 3 0 p 4 0 o 5 0 K 6 0 A 7 0 U 8 0 z 9 0 l 10 0 Y 11 0 f 12 0 A 13 0 After iterating through both strings(l is looking at the ith position at string A): 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 i p V T C P o K A U z l i Y n l 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 B 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 W 2 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 d 3 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 p 4 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 o 5 0 0 0 0 0 0 2 0 0 0 0 0 0 0 0 0 K 6 0 0 0 0 0 0 0 3 0 0 0 0 0 0 0 0 A 7 0 0 0 0 0 0 0 0 4 0 0 0 0 0 0 0 U 8 0 0 0 0 0 0 0 0 0 5 0 0 0 0 0 0 z 9 0 0 0 0 0 0 0 0 0 0 6 0 0 0 0 0 l 10 0 0 0 0 0 0 0 0 0 0 0 7 0 0 0 0 Y 11 0 0 0 0 0 0 0 0 0 0 0 0 0 8 0 0 f 12 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 A 13 0 0 0 0 0 0 0 0 4 0 0 0 0 0 0 0 Maximum length = 8, the longest common substring is "oKAUzlY" starting at position (5,6) from the table. Hence, the longest common substring in the strings A and B is "oKAUzlY". I have used the definition of the problem to iterate through the characters and keep track of the longest common substring found during this process.